Construct the bus admittance matrix for the power system shown

In reference to the power system reactance diagram, all values are given in pu. Determine the followings:

 

  1. Construct the bus admittance matrix for the power system shown in Fig. 1
  2. Use Gauss-Seidel method to solve the load flow problem

 

Table 1: Impedances and line charging (in p.u.) for the system shown in Fig.1

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Bus code p-q Impedance Shunt admittance
1-12 0.02+j0.16 j0.03
1-4 0.015+j0.12 j0.024
1-3 0.015+j0.13 j0.024
1-2 0.03+j0.25 j0.031
12-11 0.025+j0.20 j0.021
12-5 0.016+j0.09 j0.015
12-4 0.016+j0.10 j0.015
2-8 0.06+j0.60 j0.04
3-8 0.03+j0.28 j0.04
3-4 0.018+j0.16 j0.03
4-5 0.014+j0.1 j0.03
4-9 0.008+j0.065 j0.012
9-8 0.045+j0.40 j0.038
9-7 0.02+j0.18 j0.025
9-6 0.04+j0.38 j0.036
9-10 0.035+j0.32 j0.034
8-7 0.045+j0.40 j0.042
7-6 0.045+j0.40 j0.042
6-10 0.015+j0.13 j0.020

 

 

 

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Table 2: Bus data for the system shown in Fig. 1

Bus code Vinitial Pg Qg Pl Ql
1(slack) 1.0+j0 0 0 0 0
2 1.0+j0 0 0 0.66 0.26
3 1.0+j0 0 0 0.50 0.15
4 1.0+j0 0 0 0.54 0.16
5 1.0+j0 0 0 0.42 0.18
6 1.0+j0 0 0 0.64 0.28
7 1.0+j0 0. 0 0.60 0.26
8 1.0+j0 0.68 0.18 0.06
9 1.02+j0 0.84 0.24 0.09
10 1.01+j0 0.97 0.20 0.05
11 1.01+j0 0.85 0 0
12 1.03+j0 0.72 0.12 0.03

 

Please discuss your results!

 

In reference to the power system reactance diagram, all values are given in pu. Determine the followings:

 

  1. Construct the bus admittance matrix for the power system shown in Fig. 1
  2. Use Gauss-Seidel method to solve the load flow problem

click here for more information on this paper

Fig. 1

Table 1: Impedances and line charging (in p.u.) for the system shown in Fig.1

Bus code p-q Impedance Shunt admittance
1-12 0.02+j0.16 j0.03
1-4 0.015+j0.12 j0.024
1-3 0.015+j0.13 j0.024
1-2 0.03+j0.25 j0.031
12-11 0.025+j0.20 j0.021
12-5 0.016+j0.09 j0.015
12-4 0.016+j0.10 j0.015
2-8 0.06+j0.60 j0.04
3-8 0.03+j0.28 j0.04

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3-4 0.018+j0.16 j0.03
4-5 0.014+j0.1 j0.03
4-9 0.008+j0.065 j0.012
9-8 0.045+j0.40 j0.038
9-7 0.02+j0.18 j0.025
9-6 0.04+j0.38 j0.036
9-10 0.035+j0.32 j0.034
8-7 0.045+j0.40 j0.042
7-6 0.045+j0.40 j0.042
6-10 0.015+j0.13 j0.020

 

 

 

 

Table 2: Bus data for the system shown in Fig. 1

Bus code Vinitial Pg Qg Pl Ql
1(slack) 1.0+j0 0 0 0 0
2 1.0+j0 0 0 0.66 0.26
3 1.0+j0 0 0 0.50 0.15
4 1.0+j0 0 0 0.54 0.16
5 1.0+j0 0 0 0.42 0.18
6 1.0+j0 0 0 0.64 0.28
7 1.0+j0 0. 0 0.60 0.26
8 1.0+j0 0.68 0.18 0.06
9 1.02+j0 0.84 0.24 0.09
10 1.01+j0 0.97 0.20 0.05
11 1.01+j0 0.85 0 0
12 1.03+j0 0.72 0.12 0.03
 
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